10.24=k^2

Solution for 10.24=k^2 equation:

10.24=k^2

We move all terms to the left:

10.24-(k^2)=0

We add all the numbers together, and all the variables

-1k^2+10.24=0

a = -1; b = 0; c = +10.24;
Δ = b2-4ac
Δ = 02-4·(-1)·10.24
Δ = 40.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{40.96}}{2*-1}=\frac{0-\sqrt{40.96}}{-2}
=-\frac{\sqrt{}}{-2}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{40.96}}{2*-1}=\frac{0+\sqrt{40.96}}{-2}
=\frac{\sqrt{}}{-2}
$